# 10 Perfect 12 Gauge Wire, Thick Galleries

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Counseled, don't forget that the full resistance r equals cone dr, in which dr = ρ dx=a is the resistance of a skinny disk as shownon fig. 27-27. The region of the sort of disk is a = π y2, wherein y = a (b − a)x=ℓ is the radius and 0 ≤ x ≤ ℓ as proven. Thenz hf ik hf ikhf kir = ρ ℓ ρℓℓ ρ dx π =ρ ℓ π ab0 π[a (b − a)x=ℓ]2 = ℓ 1 1−1 = . ?? ab b − a [a (b − a)x=ℓ] zero π b − a(this end result relies upon on the circumstance that the flat faces and parallel circular pass-sections of the cone are equipotentialsurfaces.)Bles 19-1 and 27-1.

Use the numbers from problem 33 to discover the electric power dissipation in earth’s surroundings. If we ought to harness this energy, would it make a dent in humanity’s 1012-w electric electricity consumption?Solutionfrom equation 27-9b and trouble 33, p = v 2=r = (three hundred kv)2=(two hundred ω) = 450 mw, or approximately zero.Half of the arena’s electricpower consumption. (a) if we use equation 27-1b for the rate, then q = 5s i dt = (60 na/s) 1 t2 (2 hundred na/s2 ) 1 t3 (4 na/s3 ) 1 t4 5s = 0 2 three four zero(30 1 × a thousand 25)(25 nc) = nine.71 µc. 3problem18. A cylindrical tube of sea water consists of a complete electric modern-day of 350 ma. If the electric discipline within the water is 21 v/m, what's the diameter of the tube?.